(W^2+4W-5)(2W-1)=0

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Solution for (W^2+4W-5)(2W-1)=0 equation: 


Simplifying
(W2 + 4W + -5)(2W + -1) = 0

Reorder the terms:
(-5 + 4W + W2)(2W + -1) = 0

Reorder the terms:
(-5 + 4W + W2)(-1 + 2W) = 0

Multiply (-5 + 4W + W2) * (-1 + 2W)
(-5(-1 + 2W) + 4W * (-1 + 2W) + W2(-1 + 2W)) = 0
((-1 * -5 + 2W * -5) + 4W * (-1 + 2W) + W2(-1 + 2W)) = 0
((5 + -10W) + 4W * (-1 + 2W) + W2(-1 + 2W)) = 0
(5 + -10W + (-1 * 4W + 2W * 4W) + W2(-1 + 2W)) = 0
(5 + -10W + (-4W + 8W2) + W2(-1 + 2W)) = 0
(5 + -10W + -4W + 8W2 + (-1 * W2 + 2W * W2)) = 0
(5 + -10W + -4W + 8W2 + (-1W2 + 2W3)) = 0

Combine like terms: -10W + -4W = -14W
(5 + -14W + 8W2 + -1W2 + 2W3) = 0

Combine like terms: 8W2 + -1W2 = 7W2
(5 + -14W + 7W2 + 2W3) = 0

Solving
5 + -14W + 7W2 + 2W3 = 0

Solving for variable 'W'.

The solution to this equation could not be determined.

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